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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決
Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決 
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國二數學20點非常急~~~
Jan 14th 2014, 13:54

1.用 [-b±√(b²-4ac)]/2a 去解 x ，得

[m ± √(m²-(4)(1234)(4321))]/[(2)(1234)] = [m ± √(m²-(4)(1234)(4321))]/[(2)(4324)]

[m ± √(m²-(4)(1234)(4321))]/(1234) = [m ± √(m²-(4)(1234)(4321))]/(4324)]

(4321)(m±∆) = (1234)(m±∆)[ ∆ = √(m²-(4)(1234)(4321)) ]

3087m = (1234±4321)∆

3087m = 5555∆ or 3087m = -3087∆

let 3087m = -3087∆

m = -∆

 m² = (m²-(4)(1234)(4321)) = m² - 21328456

    (no solution. reject)

    let  

3087m = 5555∆

0.555715571m = ∆

0.308819796m² = ∆² = m² - 21328456

21328456 = ( 1 - 0.308819796 )m²

21328456 = ( 0.691180203 )m²

m = 5555

 

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